Question

How much net work is done on a 2-kg object when it speeds up from 0 m/s to 5 m/s?

Answer 1

The net work done in the 2-kg object is
`25J`

Step-by-step explanation:

Hi

Knowns

Mass,
`2kg`, initial speed
`v_(i)=0m/s` and final speed
`v_(f)=5m/s`

By using the formula of kinetic energy,
`K=(1)/(2)mv^(2)`, we can obtain that
`K_(i)=(1)/(2)mv_(i)^(2)=(1)/(2)(2kg)(0m/s)^(2)=0`, and
`K_(f)=(1)/(2)mv_(f)^(2)=(1)/(2)(2kg)(5m/s)^(2)=25J`.

As the net work by definition is,
`W_(net)=K_(f)-K_(i)=25J-0J=25J`, is the net work done in the 2-kg object to speed it up from 0 m/s to 5 m/s