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What is the equation of the line that is parallel to the given line and passes through the point (–2, 2)? y = One-fifthx + 4 y = One-fifthx + Twelve-fifths y = –5x + 4 y = –5x + Twelve-fifths

2 Answers

5 votes

Final answer:

The equation of the line parallel to the given line and passing through the point (-2, 2) is y = (1/5)x + 12/5.

Step-by-step explanation:

To find the equation of a line parallel to a given line and passing through a point, you first need to determine the slope of the given line. In this case, the slope is 1/5. Since parallel lines have the same slope, the equation of the parallel line would also have a slope of 1/5. Using the point-slope form of the equation, y - y1 = m(x - x1), where (x1, y1) is the given point, the equation of the parallel line is y - 2 = (1/5)(x - (-2)). Simplifying, we get y = (1/5)x + 2 + 2/5, which can be written as y = (1/5)x + 12/5.

User Tory Netherton
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2 votes

Answer:

y = One-fifthx + twelve-fifth

Step-by-step explanation:

User Niall Sheridan
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5.4k points