Final answer:
The balanced molecular equation for the neutralization of acetic acid with barium hydroxide is 2 CH3COOH (aq) + Ba(OH)2 (aq) → Ba(CH3COO)2 (aq) + 2 H2O (l).
Step-by-step explanation:
The molecular equation representing aqueous acetic acid neutralized by aqueous barium hydroxide is:
2 CH3COOH (aq) + Ba(OH)2 (aq) → Ba(CH3COO)2 (aq) + 2 H2O (l)
Here, acetic acid (CH3COOH) is a weak acid and barium hydroxide (Ba(OH)2) is a strong base. When combined in aqueous solutions, they react to form water (H2O) and barium acetate (Ba(CH3COO)2). The equation is balanced with two molecules of acetic acid reacting with one molecule of barium hydroxide, producing one molecule of barium acetate and two molecules of water. This reaction is an example of an acid-base neutralization.