Question

WILL DO ABSOLUTELY ANYTHING FOR THIS ONE HELP ASAP TIMES

Answer 1

Given:

The graph of a function
`y=h(x)`.

To find:

The interval where
`h(x)>0`.

Solution:

From the given graph graph it is clear that, the function before x=0 and after x=3.6 lies above the x-axis. So,
`h(x)>0` for
`x<0` and
`x>3.6`.

The function between x=0 and x=3.6 lies below the x-axis. So,
`h(x)<0` for
`0<x<3.6`.

Now,

For
`-1<x<0`, the graph of h(x) is above the x-axis. So,
`h(x)>0`.

For
`0<x<1`, the graph of h(x) is below the x-axis. So,
`h(x)<0`.

For
`1<x<2`, the graph of h(x) is below the x-axis. So,
`h(x)<0`.

Only for the interval
`-1<x<0`, we get
`h(x)>0`.

Therefore, the correct option is A.