Answer:
60 professors and 168 lecturers
Explanation:
What you have is a 2 equations system with 2 unknown variables.
Let X be the number of professors and Y be the number of lecturers. As the total of both is 228:
X + Y = 228
Then, as there are 5 professors for every 14 lecturers:
5 X = 14 Y or X = (14/5) Y
Replacing this last value of X on the first equation:
(14/5) Y + Y = 228
(14/5) Y + (5/5) Y = 228
(19/5) Y = 228
Y = 228 * (5/19)
Y = (228*5)/19
Y = 1140 / 19
Y = 60
Then we can find X:
X = (14/5) Y = (14/5) * 60 = 168
X = 168
:)