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4r^3-3r^2-4r+3 four terms use grouping

4r^3-3r^2-4r+3 four terms use grouping
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4 votes
4r^3-3r^2-4r+3
four terms
use grouping

User Shinya Koizumi
by
8.4k points

1 Answer

4 votes
It’s (4r-3)(r+1)(r-1)
User Rizky Farhan
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