Question

A student weighing 700 N climbs at constant speed to the top of an 8 m vertical rope in 10 s. The average power expended by the student to overcome gravity is most nearly

1.1 W
87.5 W
560 W
875 W
5600 W

Answer 1

The average power the student expended to overcome gravity is 560W, Watts is a units of work it is Joules /time or kg*
`m^(2)`/
`s^(3)`

Step-by-step explanation:

Weight = 700N

`F= m*g*h \\m*g= 700N\\F= 700N*h\\F=700N*8m\\F= 5600 N*m \\F=5600 J`

The power is the work in (Joules) or (N*m) in a determinate time (s) to get Watts (W) units for work

`Work= (5600 J)/(10s) = (5600 (kg*m^(2) )/(s^(2) ) )/(10 s)  \\Work= 560(kg*m^(2) )/(s^(3) ) \\Work =560 W`