Answer:
(a) In polar form complex number will be
and in radian argument is 0.378π
(b)
![6.0827\angle -9.46^(\circ)](https://img.qammunity.org/2020/formulas/mathematics/high-school/5tjconxqac6ynu9efxqa7qscyc05pwlb73.png)
angle will be 0.05255π
Explanation:
We have given
(a) 2+5i
We have to represent in polar form
We know that magnitude is given by
![√((real\ part)^2+(imaginary\ part)^2)=√(2^2+5^2)=√(29)](https://img.qammunity.org/2020/formulas/mathematics/high-school/51g4rjniqfgs7t9gx6avr21bckj0rgusj4.png)
Argument is given by
So in polar form complex number will be
![5.3851\angle 68.1985^(\circ)](https://img.qammunity.org/2020/formulas/mathematics/high-school/dpphtc520za2qucynvi23unchz82g9qcdr.png)
In radian argument will be
![68.1985* (\pi )/(180)=0.378\pi](https://img.qammunity.org/2020/formulas/mathematics/high-school/lv1gxyao6fmlxucm4pk16csmqot8f44t3a.png)
(b) We have given complex number
![-6+i](https://img.qammunity.org/2020/formulas/mathematics/high-school/6sgvxn4puwkf9ciuig8yo6ippqcyfy02dm.png)
We know that magnitude is given by
![√((real\ part)^2+(imaginary\ part)^2)=√((-6)^2+1^2)=√(37)](https://img.qammunity.org/2020/formulas/mathematics/high-school/l38o9tyg7tjxaxiasolhpyey424atw8c88.png)
Argument is given by
So in polar form complex number will be
![6.0827\angle -9.46^(\circ)](https://img.qammunity.org/2020/formulas/mathematics/high-school/5tjconxqac6ynu9efxqa7qscyc05pwlb73.png)
In radian argument will be
![-9.46* (\pi )/(180)=-0.05255\pi](https://img.qammunity.org/2020/formulas/mathematics/high-school/ocq0wg969oi8r3xo5qts0lhomusdnvbza4.png)