Question

Rewrite the following radical expressions as equivalent exponential expressions.
c.1/(3√16 )

Answer 1

`(1)/(3√(16))` =
`(16)^{(-1)/(2)}.3^(-1)`

Explanation:

We have given the expression in radical form as
`(1)/(3√(16))`

We have to convert this radical form in exponential form

We know that
`(1)/(3√(16))` can be written as
`(1)/(3√(16))=(1)/(3)* \frac{1}{(16)^{(1)/(2)}}`

Now if we write
`(1)/(3)` in exponential form then we can write as
`3^(-1)` ( property of exponent )

And
`\frac{1}{(16)^{(1)/(2)}}=(16)^{(-1)/(2)}`

So
`(1)/(3√(16))` =
`(16)^{(-1)/(2)}.3^(-1)`