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Given z1 = 1+i and z2 = 2+3i.

a. Let w = z1 ⋅ z2. Find w and the multiplicative inverse of w.
b. Show that the multiplicative inverse of w is the same as the product of the multiplicative inverses of z1 and z2.

1 Answer

2 votes

Answer:

(a)
w=2+5i-6=-4+5i

Multiplicative inverse of w will be
(1)/(-4+5i)

(B) As w is same as the product of
z_1\ and\ z_2

So there multiplicative inverse will also be same

Explanation:

We have given two complex numbers


z_1=1+i and
z_2=3+2i

(a) First we have to find
w=z_1z_2

So
w=(1+i)(2+3i)=2+3i+2i+6i^2=2+5i+6i^2

As we know that
i^2=-1

So
w=2+5i-6=-4+5i

Multiplicative inverse :

It is that number when multiply with the number which we have have to find the multiplicative inverse gives result as 1

So multiplicative inverse of w will be
(1)/(-4+5i)

Because when we multiply
-4+5i with
(1)/(-4+5i) it gives result as 1

(b) As w is same as the product of
z_1\ and\ z_2

So there multiplicative inverse will also be same

User Scaryzet
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