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What would be the first and last terms of the polynomial if it was written in standard form? (x-2)^5 ÷ (x-2)

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Answer:

In standard form the equation will be
x^4-4x^3+12x^2-16x+16

Explanation:

We have given polynomial
((x-2)^5)/((x-2))

After dividing the expression will be
(x-2)^4


(x-2)^4 can be written as
(x-2)^2* (x-2)^2


(x-2)^2* (x-2)^2=(x^2+4-4x)(x^2+4-4x)=x^4+4x^2-2x^3+4x^2+16-8x-2x^3-8x+4x^2=x^4-4x^3+12x^2-16x+16

So in standard form the equation will be
x^4-4x^3+12x^2-16x+16

User Bernard Allotey
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