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Show that each expression is equivalent to 2x. Assume x is a positive real number

6x^3/(3√27x^6)

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Answer and explanation

We have given equation
\frac{6x^3}{\sqrt[3]{27x^6}}

We have to prove that after operation it will be equal to 2x

We know that cube root of 27 is 3

And cube root of
x^6 is
x^2

So we can write the expression
\frac{6x^3}{\sqrt[3]{27x^6}}=(6x^3)/(3x^2)=2x

So after doing operation on the given expression the result will be 2x

Hence proved

User Mlathe
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