Answer: There are 6400 bacteria that will be present after 3 hours.
Explanation:
Since we have given that
Initial number of bacterial cells = 100
Each cell divides to form two new cells every 30 minutes.
Number of hours = 3 hrs
Number of minutes in 3 hours = 3\times 60 = 180 minutes
Number of 30 minutes in 3 hours =
![(180)/(30)=6](https://img.qammunity.org/2020/formulas/mathematics/high-school/tbj4tud305hyq8l7lc549zzi1xqsjttee2.png)
So, our equation becomes,
![P(x)=ab^x\\\\P(3)=100(2)^6\\\\P(3)=6400](https://img.qammunity.org/2020/formulas/mathematics/high-school/787tfrj7squmc3666h3v2bk22vnlk7kkw7.png)
Hence, there are 6400 bacteria that will be present after 3 hours.