Answer:
B. 4.
Explanation:
By the Pythagoras Theorem:
(√20)^2 = x^2 + (x - 2)^2
20 = x^2 + x^2 - 4x + 4
2x^2 - 4x - 16 = 0
x^2 - 2x - 8 = 0
(x - 4)(x + 2) = 0
x = -2, 4.
x cannot be negative so x = 4 is the answer.
B
(x-2)^2+x^2=20
2x^2-4x+4=20
2x^2-4x-16=0
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