Question

Write a balanced half-reaction describing the oxidation of solid zinc to aqueous zinc cations.​

Answer 1

`Zn^0(s)-->Z^(2+)(aq)+2e^(-)`

Step-by-step explanation:

Hello,

Considering the stated requirement, such half reaction indicates that pure zinc whose oxidation state is 0 becomes ionized zinc whose oxidation state is 2+; in such a way, its half reaction is:

`Zn^0(s)-->Z^(2+)(aq)+2e^(-)`

It is important to notice that 2 electrons were transferred since the change in the oxidation state is from 0 to +2:

Best regards.

Answer 2

Zn (s) ----> Zn2+ (aq) + 2e-

Step-by-step explanation:

Solid zinc releases two electrons, it means that it is oxidizing and at the same time changes its oxidation number, from 0 (ground state) to +2