Question

A ball is thrown straight up and reaches a maximum height of 35m. Using 9.8m/s squared as gravity, what was the initial speed of the ball?

Answer 1

26.2 m/s

Step-by-step explanation:

Given:

v = 0 m/s

Δy = 35 m

a = -9.8 m/s²

Find: v₀

v² = v₀² + 2aΔy

(0 m/s)² = v₀² + 2 (-9.8 m/s²) (35 m)

v₀ = 26.2 m/s