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If a student has 50.0 mL of a solution of 0.100 M HCI, how could they make a solution with a concentration of 0.0500 M?

User JJC
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1 Answer

2 votes

Answer:

100 ml

Step-by-step explanation:

c1×v1=c2×v2

50(0.100)=0.0500(v2)

5=0.0500(v2)

5/0.0500=0.0500/0.0500(v2)

100= v2

User Gourav
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