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Solve the system of equations:

-5x+y-4z=60
2x+4y+3z=-12
6x-3y-2x=-52

User MFR
by
7.0k points

1 Answer

1 vote

Answer:

The answer to your question is:

x = -8; y = 1 ; z = -4

Explanation:

Δ =
\left[\begin{array}{ccc}-5&1&-4\\2&4&3\\6&-3&-2\end{array}\right]

= 40 + 24 + 18 - (-4 + 45 - 96)

= 82 + 55

= 137

Δx =
\left[\begin{array}{ccc}60&1&-4\\-12&4&3\\-52&-3&-2\end{array}\right]

= - 480 - 144 - 156 - ( 24 - 540 + 832)

= -780 -316

= - 1096

Δy =
\left[\begin{array}{ccc}-5&1&-4\\2&4&3\\6&-3&-2\end{array}\right]

= 40 + 24 + 18 - ( - 4 + 45 - 96)

= 82 + 55

= 137

Δz =
\left[\begin{array}{ccc}-5&1&60\\2&4&-12\\6&-3&-52\end{array}\right]

= 1040 - 360 - 72 - ( - 104 - 180 + 1440)

= 608 - 1156

= -548

x = -1096/ 137 = -8

y = 137 / 137 = 1

z = -548 / 137 = -4

User Meshaal
by
7.2k points