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(y+8)/(y^2+7)=(?)/(y^2+7)(y-8)

(y+8)/(y^2+7)=(?)/(y^2+7)(y-8)
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(y+8)/(y^2+7)=(?)/(y^2+7)(y-8)

User MEDZ
by
8.3k points

1 Answer

6 votes

Answer:


y^(2)  - 64

Explanation:


(y+8)/(y^(2) + 7 )  = (k)/((y^(2) + 7) (y-8) )

This gives x=
y^(2) - 64

Using the formula that
x^(2) - y^(2) = (x+y)(x-y)

User Yann Ramin
by
8.9k points
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