Question

The tank of a small airplane holds 48 gallons of fuel. Seven gallons will be used for takeoff and landing. While in the air, the plane will consume an average of 10 gallons of fuel per hour. What is the maximum number of hours the plane can remain in the air

Answer 1

The maximum number of hours the small airplane can remain in the air is 4.1 hours, calculated by subtracting the seven gallons needed for takeoff and landing from the total fuel capacity, and then dividing the remaining fuel by the hourly fuel consumption.

Step-by-step explanation:

To calculate the maximum number of hours the small airplane can remain in the air, we start with the total fuel capacity and subtract the fuel used for takeoff and landing. Then we divide the remaining fuel by the hourly fuel consumption to find the hours the plane can fly.

Step 1: Subtract fuel for takeoff and landing from total capacity.

Total fuel capacity = 48 gallons

Fuel used for takeoff and landing = 7 gallons

Remaining fuel for flight = 48 gallons - 7 gallons = 41 gallons

Step 2: Divide the remaining fuel by hourly consumption.

Hourly fuel consumption = 10 gallons/hour

Maximum flight hours = Remaining fuel / Hourly fuel consumption

Maximum flight hours = 41 gallons / 10 gallons/hour = 4.1 hours

Therefore, the maximum number of hours the airplane can remain in the air is 4.1 hours.

Answer 2

4 hrs

Step-by-step explanation:

Total gallons that are in the plane = 48

Used for takeoff and landing = 7.

Remaining that is left to be used while in air = 48-7

= 41.

maximum number of hours the plane can remain in the air= Maximum of (
`(41)/(10)` )

So maximum of 4 hours.