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Find the equation of the line parallel to the graph of 4x-5y=-1 that contains the point (1,3)

User Robbyt
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Answer:

To find the equation of the line parallel to the graph, first of all find the slope of the graph by making y the subject of the formula and comparing the resulting equation with y = mx + c , knowing fully well that m stands for the slope.

So, from the equation of the graph give, y = 4x/5 +1/5, therefore the slope is 4/5. For a line to be parallel to the graph then they must have the same slope, to find the equation of the line at the given point, then we use the formula

y - y1 = m ( x - x1 )

y - 3 = 4/5 ( x - 1 )

multiply through by 5

5( y - 3 ) = 4 ( x - 1)

5y - 15 = 4x - 4

5y - 4x = - 4 + 15

so, 5y - 4x = 11 is the equation

Explanation:

User Koelkastfilosoof
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