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Given triangle QRP find the value of x and the measures of angles Q and R

Given triangle QRP find the value of x and the measures of angles Q and R-example-1

2 Answers

3 votes

Answer:

m<R= 52°

m<Q= 102°

Explanation:

Since the sum of angles in a triangle = 180°,

3x+24+2x+x=180

6x+24=180

6x=180-24

6x=156

x=26

User Bharat Kumar
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0 votes

Answer:

The value of x is 26.

Angle Q is 102° and angle R is 52°.

Explanation:

Given : Triangle QRP with
\angle Q=(3x+24)^\circ,\ \angle R=(2x)^\circ,\ \angle P=x^\circ

To find : The value of x and the measures of angles Q and R ?

Solution :

According to property of triangle,

Sum of all angles of a triangle is 180°.

i.e.
\angle Q+\angle R+\angle P=180^\circ

Substitute the angles,


(3x+24)^\circ+ (2x)^\circ+x^\circ=180^\circ


3x+24+2x+x=180


6x=180-24


6x=156


x=(156)/(6)


x=26

The value of x is 26.

So,
\angle Q=(3x+24)^\circ=3(26)+24=102^\circ


\angle R=(2x)^\circ =2(26)=52^\circ


\angle P=x^\circ =26^\circ

Therefore, angle Q is 102° and angle R is 52°.

User Ambroos
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