Question

How many grams of water can be heated 71 °C by the absorption of 970 Joules?

Answer 1

m = 3.3 g

Step-by-step explanation:

Hello!

In this case, since the specific heat of water is defined as 4.184 J(g*°C), given the temperature change and the absorbed energy, we can compute the mass of water as shown below:

`Q=mC\Delta T\\\\m=(Q)/(C\Delta T)`

Thus, we plug in the given data to obtain:

`m=(970J)/(4.184(J)/(g\°C)*71\°C)\\\\m= 3.3g`

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