Question

What is the answer to y=-3x^2+12x-33 and is it a maximum value or a minimum value

Answer 1

maximum value

Explanation:

Given a quadratic function in standard form

y = ax² + bx + c ( a ≠ 0 )

• If a > 0 then minimum value

• If a < 0 then maximum value

y = - 3x² + 12x - 33 ← is in standard form with a = - 3

Since a < 0 then maximum value