Answer:
and
![4.28(10)^(14) Hz](https://img.qammunity.org/2020/formulas/physics/high-school/riyzje113m6tef09nwpuv2ae4ktpmklq2i.png)
Step-by-step explanation:
The question in english is written below:
The eye is sensitive to electromagnetic waves whose wavelengths are approximately between
and
. What are the frequencies of these limit values knowing that the speed of light
?
There is an inverse relationship between the frequency
and the wavelength
:
(1)
Where:
is the speed of light
is the wavelength
Knowing this, we can find the frequency for the given wavelengths:
a) For
![\lambda_(1)=4(10)^(-7)m](https://img.qammunity.org/2020/formulas/physics/high-school/j1sz9h3jg34pptio61zwf428gd8vq0hnaa.png)
![\\u=(3(10)^(8) m/s)/(4(10)^(-7)m)](https://img.qammunity.org/2020/formulas/physics/high-school/dx3fnblk0ucbeeuqnngnl5mbd24otyr7qc.png)
![\\u=7.5(10)^(14)s^(-1)=7.5(10)^(14) Hz](https://img.qammunity.org/2020/formulas/physics/high-school/uozqfr05ynjb5jm9pzwj8i3is583goz2mk.png)
b) For
![\lambda_(2)=7(10)^(-7)m](https://img.qammunity.org/2020/formulas/physics/high-school/9kjmwu8i4mv0tdvyd2sgncznps7u09b5no.png)
![\\u=(3(10)^(8) m/s)/(7(10)^(-7)m)](https://img.qammunity.org/2020/formulas/physics/high-school/3oka7sj77p6aoab0p62hajqktrtir5323w.png)
![\\u=4.28(10)^(14)s^(-1)=4.28(10)^(14) Hz](https://img.qammunity.org/2020/formulas/physics/high-school/7lgprfboohofs324prpd2dijzvv89t3vbs.png)