Question

825 mL sample of an unknown HClO4 Solution requires titration with 22.62 mL of 0.2000 M NaOH to reach the equivalence point. What is the concentration of the unknown HClO4 solution? The neutralization reaction is HClO4 (Aq) + NaOH (aq) -> H2O (l) + NaClO4 (aq)

Answer 1

`M_(acid)=5.484x10^(-3)M`

Step-by-step explanation:

Hello,

By using the following formula, which comes from the assurance of the equivalence point:

`M_(acid)*V_(acid)=M_(base)*V_(base)\\M_(acid)=(M_(base)*V_(base))/(V_(acid))`

We just simply compute the acid's concentration (molarity), turning out into:

`M_(acid)=(0.2000M*22.62mL)/(825mL) \\\\M_(acid)=5.484x10^(-3)M`

Best regards.