The product of two consecutive positive even numbers is 1,224. The numbers are 34 and 36.
Solution:
Given that product of two consecutive positive even number is 1224.
Need to find the numbers
Let one even number be represented by variable x
So other consecutive even number = x + 2
As product is 1224 we can frame a equation as,
![\begin{array}{l}{\Rightarrow x(x+2)=1224} \\ {=>x^(2)+2 x=1224} \\ {=>x^(2)+2 x-1224=0}\end{array}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/tohtnd4xrt0b7nrvgsxq17a025pokn3wuy.png)
we got a quadratic equation. lets solve it by quadratic formula
According to quadratic formula for general equation a
+ bx + c = 0 , solution of the equation is given by
![x=\frac{-b \pm \sqrt{b^(2)-4 a c}}{2 a}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mkg1bcz54xxjkmnvipponepv9s5euixlgu.png)
![\text { Our equation } x^(2)+2 x-1224](https://img.qammunity.org/2020/formulas/mathematics/middle-school/87pmm8afuuebv8wzn31xmv6tunqw16vw86.png)
So in our case, a = 1, b = 2 and c = -1224
On applying quadratic formula we get
![\begin{array}{l}{x=\frac{-2 \pm \sqrt{2^(2)-4 * 1 *(-1224)}}{2 * 1}} \\\\ {x=(-2 \pm √(4+4896))/(2)} \\\\ {x=(-2 \pm √(4900))/(2)} \\\\ {x=(-2 \pm 70)/(2)} \\\\ {x=(68)/(2)=34 \text { or } x=(-72)/(2)=-36}\end{array}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/pjh54kt9dawhxcjmgt267on6mwvdffh9k2.png)
As required number is positive , ignoring the negative value
x = 34
x + 2 = 34 + 2 = 36
Hence two positive even consecutive number having product as 1224 are 34 and 36.