Question

In a certain process, 245 j of work was done by a system on its surroundings and 445 j of heat was lost to the surroundings. What was the change in E for the system?

Answer 1

Δ
`E=-690J`

Step-by-step explanation:

Hello,

Based on the first law of thermodynamics:

`W-Q=`Δ
`E`

Now, since the work is done by the system and the heat was released from the system both of them are negative, thus:

Δ
`E=-245J-445J=-690J`

Best regards.