Question

If 50.0g of CH3OH (MM = 32.04 g/mol) are dissolved in 500.0 mL of solution, what is the concentration of CH3OH in the solution?

Answer 1

The concentration (molarity) of CH3OH in the solution is 3.12 M.

Step-by-step explanation:

To find the concentration (molarity) of CH3OH in the solution, we need to use the formula:

Molarity (M) = moles of solute / volume of solution (in liters)

First, we need to convert the mass of CH3OH to moles using its molar mass: 50.0 g CH3OH * (1 mol CH3OH / 32.04 g CH3OH) = 1.560 mol CH3OH

Then, we convert the volume of the solution to liters: 500.0 mL * (1 L / 1000 mL) = 0.5000 L

Finally, we plug the values into the formula: Molarity = 1.560 mol / 0.5000 L = 3.12 M

Answer 2

Answer : The concentration of
`CH_3OH` in the solution is 3.12 M.

Explanation : Given,

Mass of
`CH_3OH` = 50.0 g

Volume of solution = 500.0 mL

Molar mass of
`CH_3OH` = 32.04 g/mole

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

`\text{Molarity}=\frac{\text{Mass of }CH_3OH* 1000}{\text{Molar mass of }CH_3OH* \text{Volume of solution (in mL)}}`

Now put all the given values in this formula, we get:

`\text{Molarity}=(50.0g* 1000)/(32.04g/mole* 500.0mL)=3.12mole/L=3.12M`

Therefore, the concentration of
`CH_3OH` in the solution is 3.12 M.