Question

X^2·(x+9)·(x−5)≥0
what are all values of x

Answer 1

Explanation:

x² ≥0 for all real values.

so we are concerned with (x+9)(x-5)≥0

x+9=0,x=-9

x-5=0,x=5

solution is values of x does not lie in these values.

so x≤-9 or x≥5