Question

What is the slope of a line perpendicular to the line whose equation is x-3y=-6x−3y=−6​

Answer 1

- 3

Explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange x - 3y = - 6 into this form

Subtract x from both sides

- 3y = - x - 6 ( divide all terms by - 3 )

y =
`(1)/(3)` x + 2 ← in slope- intercept form

with slope m =
`(1)/(3)`

Given the slope m of a line then the slope of a line perpendicular to it is

`m_(perpendicular)` = -
`(1)/(m)` = -
`(1)/((1)/(3) )` = - 3