Question

Find the 14th term of the geometric sequence below. Leave your answer in fraction form if necessary.

64,-32,16,-8

Answer 1

Explanation:

First term (a) = 64 = t1

Second term (t2) = -32

Common ratio (r) = t2/ t1 = -32 / 64 = - 1/2

Now

Tn =

`a {r}^(n - 1)`

`t14 = 64 \: ( - (1)/(2)) ^(14 - 1)`

`= 64 \: ( - (1)/(2) ) {}^(13)`

= - 64 * 1 / 8192

= - 1/128

Hope it will help :)❤