Question

10.

(05.05 MC)


Read the chemical equation.


Fe2O3 + CO → Fe + CO2


If 1.8 moles of Fe2O3 react with 2.7 moles of CO, how many moles of each product are formed? (3 points)

5.4 moles Fe and 1.8 moles CO2

2.7 moles Fe and 0.9 moles CO2

3.6 moles Fe and 5.4 moles CO2

1.8 moles Fe and 2.7 moles CO2

Answer 1

Answer: 1.8 moles Fe and 2.7 moles
`CO_2` are produced.

Step-by-step explanation:

The balanced chemical reaction is:

`Fe_2O_3+3CO\rightarrow 2Fe+3CO_2`

According to stoichiometry :

3 moles of
`CO` require 1 mole of
`Fe_2O_3`

Thus 2.7 moles of
`CO` will require=
`(1)/(3)* 2.7=0.9moles` of
`Fe_2O_3`

Thus
`CO` is the limiting reagent as it limits the formation of product and
`Fe_2O_3` is the excess reagent.

As 3 moles of
`CO` give = 2 moles of
`Fe` and 3 moles of
`CO_2`

Thus 2.7 moles of
`CO` will give =
`(2)/(3)* 2.7=1.8moles` of
`Fe` and
`(3)/(3)* 2.7=2.7moles` of
`CO_2`

Thus 1.8 moles Fe and 2.7 moles
`CO_2` are produced.