Answer:
Attention! the "x" variable was missing in your typed question, but I am assuming that the actual function was defined by:
![y=-(2)/(3) x+7](https://img.qammunity.org/2020/formulas/mathematics/middle-school/swbivv05sje5z4vcip61fvn60xhd3klwv7.png)
Table:
![\left[\begin{array}{cc}x & y\\-12&15\\-6&11\\3&5\\15&-3\end{array}\right]](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kllbxsgup03al76uxfpig5codqu0eq6smq.png)
Explanation:
In order to complete the requested table, we need to evaluate "y" for the four given values of the "x" variable in the Domain: {-12. -6, 3, 15}
Evaluation:
![y=-(2)/(3) x+7\\y=-(2)/(3) (-12)+7=8+7=15](https://img.qammunity.org/2020/formulas/mathematics/middle-school/g8eu9ms0ur2nv60skb7bf5lvwt9q6lsqd4.png)
![y=-(2)/(3) x+7\\y=-(2)/(3) (-6)+7=4+7=11](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ed4cvvulm6imsnns0dojg20zxnp5ke8xm5.png)
![y=-(2)/(3) x+7\\y=-(2)/(3) (3)+7=-2+7=5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vmzb7t7cescknu7q5f5znhumyjliz4pnb9.png)
![y=-(2)/(3) x+7\\y=-(2)/(3) (15)+7=-10+7=-3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rdka263xz6cs9klaaz0wrwensyqa8bv4mb.png)
The table therefore will be:
![\left[\begin{array}{cc}x & y\\-12&15\\-6&11\\3&5\\15&-3\end{array}\right]](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kllbxsgup03al76uxfpig5codqu0eq6smq.png)