Answer:
54 N
Step-by-step explanation:
We have two positive charges 12uC and 5 uC ,they are kept at a distance of 10cm.
We have a relation for force between two charges q1,q2 as
![F=(kq1q2)/(r^(2) )](https://img.qammunity.org/2020/formulas/physics/middle-school/7ez7gx85uyzpzu2ybt6e8b4pif3d4d18cr.png)
Value of k is
![9*10^9](https://img.qammunity.org/2020/formulas/physics/middle-school/lgj5kj24q9ylc2c9tn5yikhh3bei9n91j1.png)
On substituting the values into the equation we get,
![F=(9*10^9*12*5)/(10^9*10)\\\\ F=54N](https://img.qammunity.org/2020/formulas/physics/middle-school/53ws8t5any5rpa553ot5la1izypkqxl96i.png)
Hence the force between them is 54 N.