488,645 views
29 votes
29 votes
Write down the value of 27^-1/3

User Mutelogan
by
3.3k points

2 Answers

26 votes
26 votes

Answer:


(1)/(3)

Explanation:

using the rules of exponents


a^(-m) =
(1)/(a^(m) )


a^{(1)/(n) } =
\sqrt[n]{a}

then


27^{-(1)/(3) }

=
\frac{1}{27^{(1)/(3) } }

=
\frac{1}{\sqrt[3]{27} }

=
(1)/(3)

User Valisha
by
2.9k points
8 votes
8 votes

Answer:


(1)/(3)

Explanation:

Given:


27^{-(1)/(3)}

Rewrite 27 as 3³:


\implies (3^3)^{-(1)/(3)}


\textsf{Apply the exponent rule} \quad (a^b)^c=a^(bc):


\implies 3^{3 *-(1)/(3)}


\implies 3^{-(3)/(3)}


\implies 3^(-1)


\textsf{Apply the exponent rule} \quad a^(-n)=(1)/(a^n):


\implies (1)/(3^1)


\implies (1)/(3)

User Michael McKenna
by
3.3k points
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