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Write the equation of the line through (−2, −1) and perpendicular to 2y=3x−5.

User Shivika
by
5.2k points

2 Answers

2 votes

Answer:

Equation: y=-2/3x-
2(2)/(3)

Explanation:

y=mx +b

2y=3x-5

y=1.5x-2.5

y=-2/3x+b

(m is the negative reciprocal)

-2= 2/3+b

b=-2
(2)/(3)

Equation: y=-2/3x-
2(2)/(3)

User Ekangas
by
5.4k points
2 votes
Y=-1

Move all terms containing x to the left side of the equation.

Subtract 3x from both sides of the equation.
2x-3x=−5


Subtract 3x from 2x


−x=-5


Multiply each term in -x=−5 by −1


Multiply each term in −x=−5 by −1

(-x) ⋅ -1=(-5) ⋅-1

X=(-5) ⋅-1

multiple -5 by -1

X=5


Since x=5 is a vertical line, the slope is undefined.
Undefined

The equation of a perpendicular line to
x=5 must have a slope that is the negative reciprocal of the original slope.

M perpendicular = -1/∞
The negative reciprocal of ∞ is 0

M perpendicular is 0



Since the slope for the perpendicular line is 0 ,the line is perpendicular to the y-axis. The equation of this line is of the form
y=c when c is any real number. The equation of the line at point (-2 ,1)

Y=-1


I hope you understand this

User Inkd
by
5.1k points