Answer:
680 N
Step-by-step explanation:
We start by calculating the cheetah's acceleration knowing that goes from rest (0 speed) to 20.1 m/s in 2 seconds:
![a=(v_f-v_1)/(t) \\a=(20.1-0)/(2) =10.05 (m)/(s^2)](https://img.qammunity.org/2020/formulas/physics/middle-school/8dzvpfp88ico0mk15z9ysfs519tflwv1vt.png)
Now we use the definition of force (F):
![F=m*a\\F=68 kg * 10.05 (m)/(s^2) =683.4 N](https://img.qammunity.org/2020/formulas/physics/middle-school/e8nosaesrllofrq87no0l152tnw9d5tet7.png)
Therefore the force that accelerates the cheetah is 683.4 Newtons which we can round to 680 N to match the fourth choice shown