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A man is out fishing with his daughter. They are initially sitting at opposite ends of their 3.00-m canoe, which has a mass of 60.0 kg and is at rest in the middle of a calm lake. The man and the daughter then carefully trade places. We will neglect any resistive forces between the canoe and the water.

A)

Use these numbers: the mass of the man is 75.0 kg, and the mass of the daughter is 25.0 kg.

How far has the canoe moved, once the man and his daughter have finished trading places? _______ m

User Hetzbh
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1 Answer

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Answer:

s = 0.9375 m (to the left)

Step-by-step explanation:

We have to find the center of mass in every case

Xcm initial = (75Kg*0m+25Kg*3m+60Kg*1.5m)/(75+25+60)Kg = 1.03125m

Xcm final = (25Kg*0m+75Kg*3m+60Kg*1.5m)/(75+25+60)Kg = 1.96875m

Variation: S = 1.96875m - 1.03125m = 0.9375 m

User MisterEd
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