Question

You and a friend are spending the weekend making up missed lab experiments. You are on to second - semester material and are studying the electrostatic interaction of two charges. You notice that two charges are exerting a certain force on one another. If the distance between two electric charges doubles, then the force they exert on each other changes by how much?

2 times as large
4 times as large
1/4 as large
1/2 as large

Answer 1

`F'=(F)/(4)`

1/4 as large

Step-by-step explanation:

Lets take

q₁ and q₂ are the charge on the particle and d is the distance between them.

We know that electrostatics between two particle given as

`F=K(q_1q_2)/(d^2)`

When distance become double d'= 2 d

So new force F'

`F'=K(q_1q_2)/(d'^2)`

`F'=K(q_1q_2)/((2d)^2)`

`F'=K(q_1q_2)/(4d^2)`

`F'=(F)/(4)`

It means that force will become one forth of initial force.

So answer is 1/4 as large .