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The perimeter of a rectangle is 15x + 17 y if the length is 7/2x + 7y then find the width of the rectangle A) 4x + 3/2y B) 8x + 3y C) 8x + 10y D) 4x + 3y

User Lawonga
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1 Answer

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Answer:

A) The width of the rectangle is = 4x + (3/2)y

Explanation:

The perimeter of the rectangle = 15x + 17y

The length of the rectangle =
(7)/(2)x + 7y

Let the width of the rectangle be W.

Now, Perimeter of the Rectangle is 2(L +W)

⇒ 2(L +W) = 15x + 17y

or, 2(
(7)/(2)x + 7y + W) = 15x + 17y

or, 7x + 14y + 2W = 15x + 17y

or, 2W = 15x + 17y -( 7x + 14y)

⇒ 2W = 15x + 17y - 7x - 14y = 8x -3y

or, W =
(8x + 3y)/(2)  = (8)/(2) x + (3)/(2) y

or, Width of the rectangle = 4x + (3/2)y

User Selami
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