Question

A straight line is drawn on the surface of a 14-cm-radius turntable from the center to the perimeter. A bug crawls along this line from the center outward as the turntable spins counterclockwise at a constant 45 rpm. Its walking speed relative to the turntable is a steady 3.8 cm/s. Let its initial heading be in the positive x-direction, where the x- and y-directions are fixed relative to the laboratory. As the bug reaches the edge of the turntable (still traveling at 3.8 cm/s radially, relative to the turntable) what are the x and y components of the velocity of the bug?

Answer 1

v =
`\left[\begin{array}{c}0.66&0\end{array}\right]`m/s

Step-by-step explanation:

The position vector r of the bug with linear velocity v and angular velocity ω in the laboratory frame is given by:

`\overrightarrow{r}=vtcos(\omega t)\hat{x}+vtsin(\omega t)\hat{y}`

The velocity vector v is the first derivative of the position vector r with respect to time:

`\overrightarrow{v}=[vcos(\omega t)-\omega vtsin(\omega t)]\hat{x}+[vsin(\omega t)+\omega vtcos(\omega t)]\hat{y}`

The given values are:

`t=(x)/(v)=(14)/(3.8)=3.7 s`

`\omega=(45*2\pi)/(60s)=4.7(1)/(s)`