Question

A wire loop with 70 turns is formed into a square with sides of length ???? . The loop is in the presence of a 1.20 T uniform magnetic field ????⃗ that points in the negative y direction. The plane of the loop is tilted off the x-axis by theta=15∘ . If ????=1.50 A of current flows through the loop and the loop experiences a torque of magnitude 0.0294 N⋅m , what are the lengths of the sides ???? of the square loop, in centimeters?

Answer 1

l= 3.002 cm

Step-by-step explanation:

Given that

n= 70 turns

B= 1.2 T

θ= 15°

I= 1.5 A

τ = 0.0294 N⋅m

Lets take length of sides is l.

We know that

τ = n I A B sin θ

Area of square ,A= l²

Now by putting the value

τ = n I A B sin θ

0.0294 = 70 x 1.5 x l² x 1.2 x sin 15°

l² = 0.000901 m²

l² = 9.01 cm²

l= 3.002 cm