Answer:11
Step-by-step explanation:
her father would have to be 6 * 11 = 66
66 and 11 = 77.
you would solve as follows:
you are given that the father is 6 times as old as june.
let F = the father's age.
let J = june's age
the equation for that is F = 6J.
you are given that the sum of their ages is no less than 77.
the equation for that is F + J >= 77