Question

A​ student's course grade is based on one midterm that counts as 1010​% of his final​ grade, one class project that counts as 1010​% of his final​ grade, a set of homework assignments that counts as 4040​% of his final​ grade, and a final exam that counts as 4040​% of his final grade. His midterm score is 6666​, his project score is 8484​, his homework score is 8484​, and his final exam score is 6767. What is his overall final​ score? What letter grade did he earn​ (A, B,​ C, D, or​ F)? Assume that a mean of 90 or above is an​ A, a mean of at least 80 but less than 90 is a​ B, and so on.

Answer 1

The overall final score of the student is 75.4, in letter scale, a C.

Explanation:

Assuming that numbers are repeated (1010% means 10% and so on).

To find his overall final score, we have to take into account that it is a weighted average.

A weighted average is one where each score (x) has a specific weighing, for example, midterm's weighing in this case is 10%. If we add all weighings, we should get 100% (it is the case). The formula is:

`\mbox{Weighted average}= \sum_(i=1)^(n)x_(i)*\mbox{weighing}_(i)`

With our data:

`\mbox{Weighted average}=66*10\%+84*10\%+84*40\%+67*40\%=75.4`

As the mean is 75.4, higher than 70 but lower than 80, he earned a letter grade of C.