Question

A 37 N block rests on a horizontal surface. The coefficients of static and kinetic friction between the surface and the block are 0.8 and 0.4, respectively. A horizontal string is attached to the block and a constant tension is maintained in the string. What is the force of friction acting on the block if the tension is 24 N? Answer in units of N.

Answer 1

The frictional force acting on the block is 14.8 N.

Step-by-step explanation:

Given that,

Weight of block = 37 N

Coefficients of static = 0.8

Kinetic friction = 0.4

Tension = 24 N

We need to calculate the maximum friction force

Using formula of friction force

`f=\mu mg`

Put the value into the formula

`f=0.8*37`

`f=29.6\ N`

So, the tension must exceeds 29.6 N for the block to move

We need to calculate the frictional force acting on the block

Using formula of frictional force

`f = \mu N`

Put the value in to the formula

`f=0.4*37`

`f=14.8\ N`

Hence, The frictional force acting on the block is 14.8 N.