Answer:
We are given that 81% of respondents said that their jobs were sometimes or always stressful.
So, p = 0.81
(a) Approximate the probability that 150 or fewer workers find their jobs stressful.
x = 150
p = 0.81
n = 175
So,
![(x)/(n) =\widehat{p}](https://img.qammunity.org/2020/formulas/mathematics/college/o6ve9bnno41h3joy2x9wsmf87frunldatp.png)
![(150)/(175) =\widehat{p}](https://img.qammunity.org/2020/formulas/mathematics/college/qv8kmh40ajauv342oeued23en6wpwa6km7.png)
![0.8571=\widehat{p}](https://img.qammunity.org/2020/formulas/mathematics/college/imx6na8i21r3y4fyz7pouagjg4cajx2f9j.png)
Formula :
![z=\frac{\widehat{p}-p}{\sqrt{(p(1-p))/(n)}}](https://img.qammunity.org/2020/formulas/mathematics/college/1kbn4vby3fh1jt33bm4yviwhp4015lh1t7.png)
![z=\frac{0.8571-0.81}{\sqrt{(0.81(1-0.81))/(175)}}](https://img.qammunity.org/2020/formulas/mathematics/college/t6ljrpirunw65vovcqxsftzjyvwhmgq4x3.png)
![z=1.5882](https://img.qammunity.org/2020/formulas/mathematics/college/imnkvpnw3w84o1yetix85jom5p2yry671p.png)
Refer the z table
So, P(z<150)=0.9429
So, the probability that 150 or fewer workers find their jobs stressful is 0.9429
b) Approximate the probability that more than 140 workers find their jobs stressful.
x = 140
p = 0.81
n = 175
So,
![(x)/(n) =\widehat{p}](https://img.qammunity.org/2020/formulas/mathematics/college/o6ve9bnno41h3joy2x9wsmf87frunldatp.png)
![(140)/(175) =\widehat{p}](https://img.qammunity.org/2020/formulas/mathematics/college/cayd0ktg4c8rf7cpbd0tonb7fvq0kedh3n.png)
![0.8=\widehat{p}](https://img.qammunity.org/2020/formulas/mathematics/college/l3bia4xl39zz73fh78dsrmj4qz8omjvyy0.png)
Formula :
![z=\frac{\widehat{p}-p}{\sqrt{(p(1-p))/(n)}}](https://img.qammunity.org/2020/formulas/mathematics/college/1kbn4vby3fh1jt33bm4yviwhp4015lh1t7.png)
![z=\frac{0.8-0.81}{\sqrt{(0.81(1-0.81))/(175)}}](https://img.qammunity.org/2020/formulas/mathematics/college/1yzwzs4k7r398xj1bwiwpl59np1mgmsj3y.png)
![z=-0.3372](https://img.qammunity.org/2020/formulas/mathematics/college/qild454jsmqwyewox5ozk6a14bvweb2o8e.png)
P(z<140) = 0.3707
P(z>140)=1-P(z<140)=1-0.3707=0.6293
So, the probability that more than 140 workers find their jobs stressful is 0.6293
c) Approximate the probability that the number of workers who find their jobs stressful is between 146 and 150 inclusive.
x = 146
p = 0.81
n = 175
So,
![(x)/(n) =\widehat{p}](https://img.qammunity.org/2020/formulas/mathematics/college/o6ve9bnno41h3joy2x9wsmf87frunldatp.png)
![(146)/(175) =\widehat{p}](https://img.qammunity.org/2020/formulas/mathematics/college/etetnumuzvqoelmjf9uklpky4ssi5l35qo.png)
![0.8342=\widehat{p}](https://img.qammunity.org/2020/formulas/mathematics/college/d14vq640a45yvwl1h9u7hjy3i1034uyz3o.png)
Formula :
![z=\frac{\widehat{p}-p}{\sqrt{(p(1-p))/(n)}}](https://img.qammunity.org/2020/formulas/mathematics/college/1kbn4vby3fh1jt33bm4yviwhp4015lh1t7.png)
![z=\frac{0.8342-0.81}{\sqrt{(0.81(1-0.81))/(175)}}](https://img.qammunity.org/2020/formulas/mathematics/college/yglszh62c7cz7vx8xhx62gyl6g2xp8fc6j.png)
![z=0.816](https://img.qammunity.org/2020/formulas/mathematics/college/289v7c820rsho1eedil1aa8721eek9f8db.png)
From part a) P(z<150)=0.9429
So,P(z<150)-P(z<146)=0.9429 - 0.8342=0.1087
Hence the probability that the number of workers who find their jobs stressful is between 146 and 150 inclusive is 0.1087