Answer:
(x = 6, y = -7)
Explanation:
Solve the following system:
{4 x + 2 y = 10 | (equation 1)
x - y = 13 | (equation 2)
Subtract 1/4 × (equation 1) from equation 2:
{4 x + 2 y = 10 | (equation 1)
0 x - (3 y)/2 = 21/2 | (equation 2)
Divide equation 1 by 2:
{2 x + y = 5 | (equation 1)
0 x - (3 y)/2 = 21/2 | (equation 2)
Multiply equation 2 by 2/3:
{2 x + y = 5 | (equation 1)
0 x - y = 7 | (equation 2)
Multiply equation 2 by -1:
{2 x + y = 5 | (equation 1)
0 x+y = -7 | (equation 2)
Subtract equation 2 from equation 1:
{2 x+0 y = 12 | (equation 1)
0 x+y = -7 | (equation 2)
Divide equation 1 by 2:
{x+0 y = 6 | (equation 1)
0 x+y = -7 | (equation 2)
Collect results:
Answer: {x = 6 , y = -7