Answer:
All real numbers greater than or equal to 4,999.85 millimeters and less than or equal to 5,000.15 millimeters
Explanation:
Let
x -----> values for the center thickness of the lens
we know that
The absolute value that represent this problem is

Solve the absolute value
First case (positive)

Adds 5,000 both sides


Second case (negative)

Multiply by -1 both sides

Adds 5,000 both sides


therefore
The extreme acceptable values for the center thickness of the lens is the interval [4,999.85,5,000.15]
All real numbers greater than or equal to 4,999.85 millimeters and less than or equal to 5,000.15 millimeters