Answer:
It is significantly high, because it is greater than two standard deviations above the mean.
Explanation:
Mean =
![\mu =83.6](https://img.qammunity.org/2020/formulas/mathematics/college/vnrzrdx8rvzh0owl6p3ue841ettsifm221.png)
Standard deviation =
![\sigma = 10.3](https://img.qammunity.org/2020/formulas/mathematics/college/lueumwaq450uo9ysuoiligjzkdc3ttz2bf.png)
The range rule of thumb for 2 standard deviations :
to
![\mu+2\sigma](https://img.qammunity.org/2020/formulas/mathematics/college/o6948u4fwfas1iw8gijgurs8ticdm5ky8x.png)
Substitute the value for range
Range =
to
![83.6+2(10.3)](https://img.qammunity.org/2020/formulas/mathematics/college/v1ed1u7hcgou9pyhvawyy2xrnlwntpuv52.png)
Range =
to
![104.2](https://img.qammunity.org/2020/formulas/mathematics/college/21gl340ldb5ltlgb10xxikk3wr52okuuim.png)
Now we are asked is a pulse rate of 134.2 beats per minute significantly low or significantly high .
Since 134.2 beats per minute does lie in the range
So, It is significantly high, because it is greater than two standard deviations above the mean.